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ultraparallel

Let E be a point on the line s on the opposite side of A from C. So the perpendicular bisector of D’D a segment of s is also perpendicular to r. Compose the following two hyperbolic motions:. This is how you can see the phenomenon in Fig. Nevertheless, they are separate from each other. In the Hyperbolic Non-Euclidean World, however, we can not draw just any common perpendicular line as you see below.

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The polar of the intersecting point is the desired common perpendicular. By using this site, you agree to the Terms of Use and Privacy Policy.

hyperbolic geometry

That is, the ultraparallel lines are now normal hyperbolic parallel lines. We can draw a common perpendicular line cutting ultraparallel lines SR and TU.

This page was last edited on 7 Septemberat Then s’ meets s in an ordinary point D’. This time we used Klein’s disk model to make these concepts easy to see. We draw tangents OR and OS that contact the disk. In the Hyperbolic Non-Euclidean World, however, we can not draw just any common perpendicular line as you see below.

geometry – Prove Ultraparallel Theorem in the half-plane model – Mathematics Stack Exchange

We will occasionally talk about constructions. But they actually intersect outside the circle. Wikipedia articles needing clarification from August Articles containing proofs. Alternatively, we can construct the common perpendicular of the ultraparallel lines as follows: In hyperbolic geometrythe ultraparallel theorem states that every pair of ultraparallel lines lines that are not intersecting and not limiting parallel has a unique common perpendicular hyperbolic line.

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Views Read Edit View history. On the ultgaparallel in the Hyperbolic Non-Euclidean World, as you see, such lines exist. When endpoint U finally meets with point Sand ultrwparallel line TU becomes straight line T’U’the common perpendicular line becomes a tangential line to the model disk. Thurston, Three-Dimensional Geometry ultraparallek Topology, p Hyperbolic geometry Theorems in geometry.

Ultraparallel – definition of Ultraparallel by The Free Dictionary

They are the same distance from r and both lie on s. Klein disk has the chord straight line RS. Rather s’ would be asymptotically parallel to both s and r. It is only one, ultraparallwl. In Euclidean plane, there is not a single pair of lines that neither intersects nor is parallel. That is, they are forming parallel lines.

They are not parallel lines because they have no common point at infinity the disk edge. In Euclidean plane, we can not draw a straight line that cuts perpendicularly non-parallel lines.

Now all straight lines that cut the chord RS are perpendicular to it. The red lines are simply for your convenience in observation. Let E be a point on the line s on the opposite side of A from C.

If one of the chords happens to be a diameter, we do not have a pole, but in this case any chord perpendicular to the diameter it is also perpendicular in the Beltrami-Klein model, and so we draw a line through the pole of the other line intersecting the diameter at right angles to get the common perpendicular. Nevertheless, they are separate from each other. Chords RS and TU have a common point at infinity disk edge now. Compose the following two hyperbolic motions:.

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Retrieved from ” https: Straight line OO’ is perpendicular to both chord RS and TU but it is tangent to the disk and does not pass its inside. If r and s were asymptotically parallel rather than ultraparallel, this construction would fail because s’ would not meet s.